-0.1x^2+3.075x-10=0

Solution for -0.1x^2+3.075x-10=0 equation:

-0.1x^2+3.075x-10=0

a = -0.1; b = 3.075; c = -10;
Δ = b2-4ac
Δ = 3.0752-4·(-0.1)·(-10)
Δ = 5.455625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.075)-\sqrt{5.455625}}{2*-0.1}=\frac{-3.075-\sqrt{5.455625}}{-0.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.075)+\sqrt{5.455625}}{2*-0.1}=\frac{-3.075+\sqrt{5.455625}}{-0.2}
$